A Python interface to libcurl
192.27 KB
built 2026-10-17 12:05:34 GMT
Description
PycURL is a Python interface to libcurl. PycURL can be used to fetch
objects identified by a URL from a Python program, similar to the
urllib Python module. PycURL is mature, very fast, and supports a lot
of features.
Dependencies
24 totalRequires18
- ld-linux-riscv64-lp64d.so.1()(64bit)
- ld-linux-riscv64-lp64d.so.1(GLIBC_2.27)(64bit)
- libc.so.6()(64bit)
- libc.so.6(GLIBC_2.27)(64bit)
- libcrypto.so.4()(64bit)
- libcrypto.so.4(OPENSSL_4.0.0)(64bit)
- libcurl(riscv-64) >= 8.18.0~
- libcurl.so.4()(64bit)
- libssl.so.4()(64bit)
- libssl.so.4(OPENSSL_4.0.0)(64bit)
- python(abi) = 3.15
- rpmlib(CompressedFileNames) <= 3.0.4-1
- rpmlib(FileDigests) <= 4.6.0-1
- rpmlib(PartialHardlinkSets) <= 4.0.4-1
- rpmlib(PayloadFilesHavePrefix) <= 4.0-1
- rpmlib(PayloadIsZstd) <= 5.4.18-1
- rpmlib(TildeInVersions) <= 4.10.0-1
- rtld(GNU_HASH)
Provides6
- python-pycurl = 7.47.0-3.rvmock0_nc.fc45
- python3-pycurl = 7.47.0-3.rvmock0_nc.fc45
- python3-pycurl(riscv-64) = 7.47.0-3.rvmock0_nc.fc45
- python3.15-pycurl = 7.47.0-3.rvmock0_nc.fc45
- python3.15dist(pycurl) = 7.47
- python3dist(pycurl) = 7.47
ObsoletesNo Obsoletes
ConflictsNo Conflicts
RecommendsNo Recommends
SuggestsNo Suggests
SupplementsNo Supplements
EnhancesNo Enhances
Files
145
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Component of
buildroots that installed this RPMBuildroot ![]() |
Created | State |
|---|---|---|
| f45-build-56129-966 | 2026-10-30 14:03:08 | expired |
| f45-build-37948-718 | 2026-10-18 03:58:20 | expired |
| f45-build-34834-691 | 2026-10-17 20:26:56 | expired |
| f45-build-34754-690 | 2026-10-17 20:15:16 | expired |
| f45-build-34730-690 | 2026-10-17 20:14:23 | expired |
| f45-build-34488-686 | 2026-10-17 19:18:23 | expired |
Buildroots 1–6 of 6

